Physics Electrostatics Potential & Capacitance JEE (Main) / AIEEE Problems Previous Years - ( Capacitance ) MCQ (Single Correct)

A uniform surface charge of density σ is given to a quarter of a disc extending upto infinity in the first quadrant of x - y plane. The center of the disc is at the origin O. Find the z - component of the electric field at the point (0, 0, z) and the potential difference between the points (0, 0, d) & (0, 0, 2d).

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, ⏐ d ⏐

Sol. In the remaining three quadrants, put three more quarter sheets to convert this given arrangement to that of infinite sheet. Now contribution from all the four quarters to the z - component will be same. Hence due to a quarter component of E.F. along z axis at point (0 , 0 , z) will be ,

= =

Hence potential difference between points (0 , 0 , d) and (0 , 0 , 2d) will be ,

V 2d - V d = - . ; where = d z ; = =

V 2d - V d = - . dz = - ; V d - V 2d = ⏐ d ⏐

, ⏐ d ⏐

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